0=-0.5x^2+25x-73

Solution for 0=-0.5x^2+25x-73 equation:

0=-0.5x^2+25x-73

We move all terms to the left:

0-(-0.5x^2+25x-73)=0

We add all the numbers together, and all the variables

-(-0.5x^2+25x-73)=0

We get rid of parentheses

0.5x^2-25x+73=0

a = 0.5; b = -25; c = +73;
Δ = b2-4ac
Δ = -252-4·0.5·73
Δ = 479
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-\sqrt{479}}{2*0.5}=\frac{25-\sqrt{479}}{1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+\sqrt{479}}{2*0.5}=\frac{25+\sqrt{479}}{1}
$